Chemistry Labs

Problem 2

In a gaseous mixture of CO and COX2\ce{CO2}, a mass ratio of carbon : oxygen = 1 : 2 was determined. 2.1 Calculate the mass percent composition of the mixture. 2.2 Calculate the volume percent composition. 2.3 Indicate the values of the carbon : oxygen mass ratio for which both gases cannot be present simultaneously in the mixture.
Step 3 of 4: Volume percent
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vol. % =mol %  ⇒  50 % CO+50 % COX2\text{vol.\,\% } = \text{mol\,\%}\;\Rightarrow\; 50\,\%\ \ce{CO} + 50\,\%\ \ce{CO2}
Analysis

For ideal gases the volume fraction equals the mole fraction; since x=yx = y, the mixture is 50 % CO+50 % COX250\,\%\ \ce{CO} + 50\,\%\ \ce{CO2} by volume.