Chemistry Labs

Problem 1

Compounds of divalent platinum with the general formula PtXX2(amine)X2\ce{PtX2(amine)2} (X = ClX2\ce{Cl2}, SOX4X2−\ce{SO4^{2-}}, malonate, etc.) have attracted great scientific interest because of their antitumour activity. The best-known clinically used compound is PtClX2(NHX3)X2\ce{PtCl2(NH3)2}, in which platinum has square-planar coordination; it has two geometrical isomers of which only one is antitumour-active. 1.1 Sketch the spatial structures of the two possible isomers. 1.2 How many isomers does PtBrCl(NHX3)X2\ce{PtBrCl(NH3)2} have? Sketch all of them. 1.3 The amine ligands may be replaced by one ligand with two donor atoms (N), e.g. 1,2-diaminoethane (en). Show that PtBrCl(en)\ce{PtBrCl(en)} has only one stable structure. 1.4 In aqueous solution the compounds can isomerise through dissociation of a ligand and transient replacement by water; ClX−\ce{Cl^-} and BrX−\ce{Br^-} are replaced relatively easily, the amine ligands only with difficulty. PtClX2(en)\ce{PtCl2(en)} reacts with BrX−\ce{Br^-} (molar ratio 1 : 2) at room temperature. Which compounds form and in what proportion? (Pt–Br and Pt–Cl bonds are equally strong; neglect hydrolysis.) 1.5 Using a chemical equilibrium equation, show why hydrolysis of PtClX2(NHX3)X2\ce{PtCl2(NH3)2} hardly occurs in blood but does occur inside cells (Cl− concentration is high in blood, low in cells). 1.6 After hydrolysis in the tumour cell a reactive platinum ion bearing two NHX3\ce{NH3} ligands binds to cellular DNA at a guanine N atom; a second bond to a guanine of the same strand can then form. Show by calculation which of the two isomers of 1.1 can form this bond. (Pt–N distance = 210 pm; distance between DNA bases = 320 pm.)
Step 4 of 4: Which isomer can bridge two guanines
Intuition

Ask how far apart the two leaving-group (N-binding) sites sit in each isomer.

dcis=2102=297 pm<320 pm;dtrans=2×210=420 pm>320 pmd_{cis} = 210\sqrt{2} = 297\ \text{pm} < 320\ \text{pm};\qquad d_{trans} = 2 \times 210 = 420\ \text{pm} > 320\ \text{pm}
Analysis

For the cis isomer the two exchangeable sites subtend 90°, giving a separation 2102=297210\sqrt{2} = 297 pm — close enough to the 320 pm guanine spacing to bridge with minimal distortion. For the trans isomer the sites are opposite, 2×210=4202 \times 210 = 420 pm, far beyond reach. Hence only cis-PtClX2(NHX3)X2\ce{PtCl2(NH3)2} can make the second guanine bond — consistent with cisplatin being the active drug.