Chemistry Labs

International Chemistry Olympiad · 2002

Problems

  1. Problem 4Production of methanol. Methanol (CHX3OH\ce{CH3OH}) is used for gasoline additives and many plastics. A factory is based on CO+2 HX2→CHX3OH\ce{CO + 2H2 -> CH3OH}; the HX2\ce{H2} and CO are obtained by reforming CHX4+HX2O→CO+3 HX2\ce{CH4 + H2O -> CO + 3H2}. The plant has three units: the reformer, the methanol reactor, and a separator that removes methanol from CO and HX2\ce{H2}. Positions α, β, γ, δ are: α = feed to reformer (CHX4\ce{CH4}, HX2O\ce{H2O}), β = gas entering the methanol reactor (CO, HX2\ce{H2}), γ = stream leaving the reactor before separation (CO, HX2\ce{H2}, CHX3OH\ce{CH3OH}), δ = recycled/burnt excess CO and HX2\ce{H2} after the separator. The methanol flow at γ is n(CHX3OH,γ)=1000n(\ce{CH3OH}, \gamma) = 1000 mol s−1^{-1}, and the design converts 2/3 of the CO to methanol; the reformer reaction goes to completion. (4.1) Calculate the flows of CO and HX2\ce{H2} at β. (4.2) Calculate the flows of CO and HX2\ce{H2} at γ. (4.3) Calculate the flows of CHX4\ce{CH4} and HX2O\ce{H2O} needed at α. (4.4) All species are gaseous at γ; with total pressure p=10p = 10 MPa, calculate the partial pressures of CO, HX2\ce{H2} and CHX3OH\ce{CH3OH} at γ using pi=p ni/ntotp_i = p\, n_i/n_{\mathrm{tot}}. (4.5) When the reactor is large enough the reaction reaches equilibrium and the partial pressures obey Kp=p(CHX3OH) p0p(CO) p(HX2)2K_p = \dfrac{p(\ce{CH3OH})\,p^0}{p(\ce{CO})\,p(\ce{H2})^2} with p0=0.1p^0 = 0.1 MPa. Calculate KpK_p (the corresponding temperature from the graph of log⁡Kp\log K_p vs TT is about 630 K).Solutions: 1