Chemistry Labs

International Chemistry Olympiad · 2013

Problems

  1. Problem 1The “clathrate gun” scenario: ocean-floor methane hydrates could decompose explosively as oceans warm. Upon decomposition of 1.00 g of a methane hydrate of fixed composition at 25 °C and 101.3 kPa, 205 cm3^3 of methane is released. (a) Determine nn in CHX4 ⋅n HX2O\ce{CH4 \cdot n H2O}. (b) Real hydrate is close to CHX4 ⋅6 HX2O\ce{CH4 \cdot 6 H2O}, stable at 1 atm down to its decomposition at −81-81 °C; write its decomposition to methane and ice, ΔH=+17.47\Delta H = +17.47 kJ mol−1^{-1}. Assuming ΔH\Delta H is T- and p-independent, that the volume change equals the released methane volume, and that methane is ideal, find the external pressure at which decomposition occurs at −5-5 °C. (c) What is the minimum possible depth of pure liquid water at which methane hydrates are stable? First choose the minimum temperature at which the hydrate can coexist with liquid water: 272.9 K, 273.15 K, or 273.4 K. (d) In Lake Baikal, hydrate samples raised from 1400 m began to decompose at 372 m depth (ΔfusH\Delta_{fus}H(ice) = 6.01 kJ mol−1^{-1}); find the water temperature at 372 m. (e) Total methane in hydrates is ≥5×1011\geq 5 \times 10^{11} t; by how many degrees would Earth's atmosphere heat if it all burned (ΔcH(CHX4)=−889\Delta_c H(\ce{CH4}) = -889 kJ mol−1^{-1}, atmospheric heat capacity 4×10214 \times 10^{21} J K−1^{-1})?Solutions: 1
  2. Problem 2The Hill reaction dissects photosynthesis. (a) Write the overall equation of plant photosynthesis, reducing COX2\ce{CO2} to {CHX2O}\{\ce{CH2O}\}. (b) Hill found that isolated chloroplasts do not evolve OX2\ce{O2} in light even with COX2\ce{CO2}, but do so upon adding potassium ferrioxalate KX3[Fe(CX2OX4)X3]\ce{K3[Fe(C2O4)3]} (with excess oxalate) without COX2\ce{CO2}. Give the oxidant and reducing agent in natural photosynthesis and in the Hill reaction. (c) Hill measured evolved OX2\ce{O2} with haemoglobin (Hb binds OX2\ce{O2} 1:1, initial [Hb]=0.6×10−4[\text{Hb}] = 0.6 \times 10^{-4} mol dm−3^{-3}); at [FeXIII]=2.0×10−4[\ce{Fe^{III}}] = 2.0 \times 10^{-4} mol dm−3^{-3} the HbO2_2 fraction saturates at about 75 %. Estimate the Fe/OX2\ce{O2} ratio, write the Hill reaction equation, and calculate its ΔG\Delta G at T=298T = 298 K, p(OX2)=1p(\ce{O2}) = 1 mmHg, pH = 8, standard concentrations of other species (E∘E^{\circ}: OX2+4 HX++4 eX−→2 HX2O\ce{O2 + 4H+ + 4e- -> 2H2O} +1.23 V; [Fe(CX2OX4)X3]X3−+eX−→[Fe(CX2OX4)X3]X4−\ce{[Fe(C2O4)3]^{3-} + e- -> [Fe(C2O4)3]^{4-}} +0.05 V). Is it spontaneous? (d) Isolated chloroplasts were irradiated 2 h with 672 nm light of 0.503 mJ s−1^{-1}, producing 47.6 mm3^3 OX2\ce{O2} (10 °C, 740 mmHg). Calculate the quantum requirement (photons per electron transferred). (e) Conclusions: are water oxidation and COX2\ce{CO2} reduction spatially separated? Is OX2\ce{O2} produced from COX2\ce{CO2}? Does water oxidation require light? Do most chlorophylls participate directly? Does each photon transfer one electron?Solutions: 1