Chemistry Labs

Problem 2

Kinetic isotope effect (KIE) and zero-point vibrational energy (ZPE). The harmonic oscillator model gives the vibrational frequency ν=12πkμ\nu = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{\mu}}, where kk is the force constant and μ=m1m2m1+m2\mu = \dfrac{m_1 m_2}{m_1 + m_2} is the reduced mass. Vibrational energies are En=(n+12)hνE_n = (n + \tfrac{1}{2})h\nu (n=0,1,2,…n = 0, 1, 2, \dots), and the zero-point energy is ZPE=12hν\text{ZPE} = \tfrac{1}{2}h\nu. (a) Calculate the reduced masses μCH\mu_{\ce{CH}} and μCD\mu_{\ce{CD}} in atomic mass units (u), taking m(C)=12.00m(\ce{C}) = 12.00 u, m(H)=1.008m(\ce{H}) = 1.008 u, and m(D)=2.014m(\ce{D}) = 2.014 u. (b) Given kCH=kCDk_{\ce{CH}} = k_{\ce{CD}} and the C−H\ce{C-H} stretching wavenumber ν~CH=2900 cm−1\tilde{\nu}_{\ce{CH}} = 2900\ \text{cm}^{-1}, calculate the C−D\ce{C-D} stretching wavenumber ν~CD\tilde{\nu}_{\ce{CD}} (cm−1^{-1}). (c) Calculate ZPECH\text{ZPE}_{\ce{CH}} and ZPECD\text{ZPE}_{\ce{CD}} in kJ mol−1^{-1}. (d) Calculate the difference in bond dissociation energies ΔBDE=BDECD−BDECH\Delta \text{BDE} = \text{BDE}_{\ce{CD}} - \text{BDE}_{\ce{CH}} (kJ mol−1^{-1}). (e) Assuming Ea≈BDEE_a \approx \text{BDE} and identical Arrhenius pre-exponential factors, calculate the theoretical primary KIE kCH/kCDk_{\ce{CH}}/k_{\ce{CD}} at 25 ∘C25\ ^{\circ}\text{C}. (f) In the chromic acid oxidation of diphenylmethanol, measured first-order rate constants are kCH=0.012 min−1k_{\ce{CH}} = 0.012\ \text{min}^{-1} and kCD=0.0018 min−1k_{\ce{CD}} = 0.0018\ \text{min}^{-1}. Compare this experimental ratio with the theoretical value and determine whether C−H\ce{C-H} bond cleavage is rate-determining.
Step 6 of 6: Experimental comparison and mechanistic conclusion
(kCHkCD)exp=0.012 min−10.0018 min−1=6.67≈6.7⇒C−H cleavage is rate-determining\left(\dfrac{k_{\ce{CH}}}{k_{\ce{CD}}}\right)_{\text{exp}} = \dfrac{0.012\ \text{min}^{-1}}{0.0018\ \text{min}^{-1}} = 6.67 \approx 6.7 \Rightarrow \ce{C-H} \text{ cleavage is rate-determining}
Analysis

The measured ratio kCH/kCD=0.012/0.0018=6.7k_{\ce{CH}}/k_{\ce{CD}} = 0.012 / 0.0018 = 6.7 is in excellent agreement with the theoretical primary KIE (6.5). If C−H\ce{C-H} cleavage occurred after the rate-determining step, a secondary KIE close to 1 would be observed; therefore, the C−H\ce{C-H} bond-breaking step is indeed the rate-determining step.

Common pitfall. Do not confuse primary KIE (cleavage of the bond directly involved in the reaction, ratio 6–8) with secondary KIE (isotopic substitution on an adjacent atom, ratio usually 0.8–1.4).