Chemistry Labs

Problem 1

Molecular imaging is a powerful tool in medical diagnostics. The nuclear isomer 99mTc^{99m}\ce{Tc} (m = metastable) is an excellent γ-emitter (t1/2=6.015t_{1/2} = 6.015 h) obtained by β− decay of a mother nuclide in a technetium generator as [99mTcOX4]−[^{99m}\ce{TcO4}]^-. (a) Identify the mother nuclide A and the emitted particle B in A→X99mX2299mTc+B\ce{A -> ^{99m}Tc + B}. (b) An eluate from a 99mTc^{99m}\ce{Tc} generator has an activity of 12.5 GBq (1 GBq = 10910^{9} decays per second). Calculate how many moles of 99mTc^{99m}\ce{Tc} are present. (c) For standard imaging about 200 MBq are administered to a patient. Assuming no activity is lost through excretion, calculate how many hours the patient has to wait until the injected activity decreases to under 1% of the starting activity.
Step 1 of 3: Mother nuclide
99Mo→99mTc+β− (+νˉ)^{99}\ce{Mo} \rightarrow {}^{99m}\ce{Tc} + \beta^{-}\ (+\bar{\nu})
Analysis

In β− decay a neutron turns into a proton, so the daughter has the same mass number and ZZ increased by one: 99Mo^{99}\ce{Mo} (Z=42Z=42) decays to 99mTc^{99m}\ce{Tc} (Z=43Z=43) emitting an electron. In the generator the parent travels as molybdate [99MoOX4]2−[^{99}\ce{MoO4}]^{2-} and elutes as pertechnetate [99mTcOX4]−[^{99m}\ce{TcO4}]^{-}.