Chemistry Labs

Problem 2

Astatine is the rarest naturally occurring element in the Earth's crust, with a total estimated mass of 30 g at any point in time; assume all astatine is the most stable naturally occurring isotope 219^{219}At. (a) Estimate how many At atoms occur naturally on Earth at any point in time. (b) Bismuth, obtained as a by-product of lead purification, is concentrated by adding magnesium and calcium to a lead–bismuth mixture; bismuth forms alloy A containing 7.91 % Ca and 9.60 % Mg by mass, with no lead. Determine the empirical formula of alloy A. (c) Alloy A reacts with chlorine gas to form bismuth and two ionic compounds B and C in a 2:1 ratio. Write the formulae of B and C. (d) Astatine is made by bombarding 83209^{209}_{83}Bi with α\alpha particles; the nuclei fuse to form yx^{x}_{y}At and two neutrons. Write the mass and atomic numbers of the astatine isotope. (e) Excess bismuth is removed with concentrated nitric acid, forming bismuth(III) nitrate, water and a colourless gas of molar mass 30.01 g mol−1^{-1}. Write the equation. (f) BrAt is made in two steps: BrX2\ce{Br2} reacts with D to give only E, and E reacts with AtX2\ce{At2} to give BrAt and D; the mass spectrum of E shows two major peaks of nearly equal intensity at m/z 205.82 and 207.82. Write the formulae of D and E. (g) 3.60 g of BrAt is synthesised; the half-life of this At isotope is 433 minutes. How long (to the nearest hour) until only 3.65 mg of BrAt remains?
Step 1 of 5: Atoms of astatine on Earth
N=30 g219 g mol−1×6.022×1023=8×1022 atomsN = \frac{30\ \text{g}}{219\ \text{g mol}^{-1}} \times 6.022 \times 10^{23} = 8 \times 10^{22}\ \text{atoms}
Analysis

n=m/M=30/219=0.137n = m/M = 30/219 = 0.137 mol, so N=nNA=8×1022N = n N_A = 8 \times 10^{22} atoms; one significant figure suffices given the estimate.