Measuring heat with a coffee-cup calorimeter
Drop a hot metal block into water inside an insulated cup and deduce the metal’s specific heat from q = mcΔT.
Goal
Use q = mcΔT for both the water and the metal, and extract the metal’s specific heat capacity from the measured ΔT.
Apparatus and reagents
Insulated foam cup, thermometer, balance, 50 g of water, and ~25 g blocks of Al, Cu and Pb heated in a water bath.
Procedure
- Weigh 50 g of water into the insulated cup and record its temperature, T₁ = 25.0 °C.
- Heat a 25 g metal block to about 95 °C in a water bath, then transfer it quickly into the cup.
- Stir gently and read the highest steady temperature T₂.
- Repeat for the other metals and compare the ΔT values.
What to observe
- The temperature rise differs strongly between metals: Al warms the water ≈ 7.5 K, Cu ≈ 3.3 K and Pb only ≈ 1.1 K for the same mass and initial temperature.
- The thermometer shows a fast rise then a plateau — the thermal equilibrium where the heat lost by the metal equals the heat gained by the water.
Explanation
With heat losses neglected, q_metal = −q_water, so m_metal·c_metal·(T₂−95) = −m_water·c_water·(T₂−25). Solving for c_metal recovers 0.90, 0.39 and 0.13 J g⁻¹ K⁻¹ for Al, Cu and Pb: a small specific heat means the same mass stores less thermal energy. In a real cup a few percent of the heat escapes or is absorbed by the cup itself, so measured ΔT runs slightly low.
History of the experiment
Chemists behind it
Related topics
Virtual experiment: a simplified model to build intuition. It does not replace real lab work or safety training; never repeat chemistry at home without supervision.