Hybrid orbitals and delocalization
Render sp, sp² and sp³ lobes in 3D, then connect each hybridization to geometry, resonance and the CIP stakes of stereoisomerism.
Goal
Recognise a carbon’s hybridization from its geometry (sp³ tetrahedral, sp² planar, sp linear) and use it to judge where resonance or hyperconjugation can operate.
Apparatus and reagents
The orbital viewer below; examples , , and the allyl cation.
Procedure
- Set type = 2 (sp³) and rotate: count the four equivalent lobes pointing to tetrahedron corners.
- Set type = 1 (sp²): three lobes lie in a plane at 120°; the unused p orbital sticks out perpendicular.
- Set type = 0 (sp): two lobes opposite at 180°, two perpendicular p orbitals — the recipe for triple bonds.
- Assign the hybridization of every carbon in and state where the empty p orbital must sit for resonance.
What to observe
- sp³ lobes reach 109.5°; sp² lobes are coplanar at 120°; sp lobes are collinear at 180° — the mixing ratio n s + m p dictates the angle.
- An sp² carbon always keeps a free p orbital; alignment of neighbouring p orbitals is exactly what resonance and hyperconjugation need.
Explanation
Hybridization is a bookkeeping of the valence basis: mixing one s with k p orbitals gives k+1 equivalent lobes whose geometry minimises repulsion — and leaves 3−k pure p orbitals. The leftover p system explains resonance ( ↔ ) and hyperconjugation (σ C–H donation into an adjacent p or π* orbital), the same electronic bookkeeping behind the CIP description of stereogenic centres.
History of the experiment
Chemists behind it
Related topics
Virtual experiment: a simplified model to build intuition. It does not replace real lab work or safety training; never repeat chemistry at home without supervision.