pH-metric titration and the buffer region
Titrate acetic acid with NaOH and watch the curve flatten where the pair buffers the pH — at half-equivalence pH = pKa.
Goal
Locate the buffer plateau and read pKa of acetic acid at the half-equivalence point (pH ≈ 4.76); explain why the slope is minimal there.
Apparatus and reagents
Beaker of 0.1 mol/L acetic acid, burette of 0.1 mol/L NaOH, calibrated pH meter with glass electrode, magnetic stirrer.
Procedure
- Select the weak-acid option (acid = 1) with C = 0.1 mol/L.
- Increase Vb step by step and record pH; mark where the curve is flattest — the buffer plateau.
- Find the equivalence volume Ve at the steepest jump, then set Vb = Ve/2 and read pH: it equals pKa.
- Compare the initial pH and the equivalence pH (>7) with a strong-acid titration (acid = 0).
What to observe
- The curve starts higher than for a strong acid and runs through a nearly flat plateau centred on pH ≈ pKa before jumping steeply past equivalence to pH ≈ 12–13.
- At Vb = Ve/2 the acid and its conjugate base are present in equal amounts and pH ≈ 4.76, the pKa of acetic acid; at equivalence the solution is basic because is a weak base.
Explanation
As NaOH is added, is converted into . While comparable amounts of both coexist, the Henderson–Hasselbalch relation keeps pH almost constant — the buffer region — and at half-neutralisation pH = pKa. At equivalence only remains, so the solution is basic.
History of the experiment
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