Chemistry Labs

Grade 12

Isotopes and nuclear decay: alpha, beta and gamma

The nuclear algebra of nuclide notation and decay modes, balancing nuclear equations, and mapping the 14-step uranium-238 decay chain.

IntuitionIntuition: unstable cores seeking lighter configurations

While ordinary chemical reactions only rearrange peripheral electrons leaving atomic nuclei untouched, radioactivity transforms the elemental identity of the atom itself. Protons in a nucleus are squeezed into a femtometer space, held together by the attractive strong nuclear force while intensely repelling one another through their positive electric charges. When the delicate balance between strong attraction and electrostatic repulsion falters, the nucleus discharges its excess mass or energy as fast particles or energetic photons.

Every spontaneous nuclear decay adheres to rigid conservation laws: the total nucleon count and the total electric charge are conserved in every event. An alpha decay expels a tightly bound bundle of two protons and two neutrons; beta decays transmute a nucleon identity with the emission of a beta particle and a neutrino; and gamma transitions release excess excitation energy without changing the number of protons or neutrons.

Interactive nuclear decay scheme. Explore alpha decay of ²³⁸U, beta-minus decay of ¹⁴C, isomeric gamma transition of ⁹⁹ᵐTc, and the complete 14-step decay series ending at stable ²⁰⁶Pb.

SchoolCore concepts: nuclide notation and the decay modes

Definition: Nuclide notation and radioactive decay

A nuclide is represented as XZAX2Z2AX\ce{^A_Z X}, where ZZ is the atomic number (number of protons), AA is the mass number (total nucleons), and N=A−ZN = A - Z is the neutron number. Radioactive decay is the spontaneous transition of an unstable nucleus into a daughter nucleus accompanied by the emission of ionizing radiation. Light stable nuclei follow N/Z≈1N/Z \approx 1, whereas heavier stable nuclei require N/Z≈1.5N/Z \approx 1.5 to offset electrostatic proton repulsion along the belt of stability.

Comparison of alpha, beta and gamma radiation
Radiation modeCompositionCharge (e)Rest mass (u)Ionizing powerTypical shielding
Alpha (α)Helium-4 nucleus+24.0015Very highSheet of paper, skin
Beta-minus (β⁻)Fast electron-10.00055ModerateFew mm aluminium
Beta-plus (β⁺)Positron (antielectron)+10.00055ModerateAnnihilation shielding
Gamma (γ)Energetic photon00LowThick lead, dense concrete
XZAX2Z2AX→XZ−2A−4X2Z−22A−4Y+X24X2224He(α),XZAX2Z2AX→XZ+1AX2Z+12AY+X−10X2−120e+νˉXe(β−),XZAX2Z2AXX∗→XZAX2Z2AX+γ(γ)\ce{^A_Z X -> ^{A-4}_{Z-2} Y + ^4_2He} \quad (\alpha), \qquad \ce{^A_Z X -> ^A_{Z+1} Y + ^0_{-1}e + \bar{\nu}_e} \quad (\beta^-), \qquad \ce{^{A}_Z X^* -> ^A_Z X + \gamma} \quad (\gamma)

Balancing nuclear equations depends on two universal conservation principles: the sum of mass numbers AA on both sides must match (∑Areactants=∑Aproducts\sum A_{\text{reactants}} = \sum A_{\text{products}}), and the total charge numbers ZZ must balance (∑Zreactants=∑Zproducts\sum Z_{\text{reactants}} = \sum Z_{\text{products}}). In the natural uranium-238 decay chain, X92238X2922238U\ce{^{238}_{92}U} undergoes 8 alpha decays and 6 beta-minus decays to reach stable X82206X2822206Pb\ce{^{206}_{82}Pb}. We can verify both balances: ΔA=8×(−4)+6×(0)=−32\Delta A = 8 \times (-4) + 6 \times (0) = -32, so 238−32=206238 - 32 = 206; and ΔZ=8×(−2)+6×(+1)=−10\Delta Z = 8 \times (-2) + 6 \times (+1) = -10, so 92−10=8292 - 10 = 82, identifying lead precisely.

Example: Balancing sequential beta decays in the thorium series

In the thorium series, radium-228 (X88228X2882228Ra\ce{^{228}_{88}Ra}) decays by beta-minus emission into an actinium isotope, which in turn decays by beta-minus emission into a thorium isotope. Write both balanced nuclear equations, stating the emitted antineutrino, and identify the resulting thorium nuclide.

Solution

Step 1: X88228X2882228Ra→X89228X2892228Ac+X−10X2−120e+νˉXe\ce{^{228}_{88}Ra -> ^{228}_{89}Ac + ^0_{-1}e + \bar{\nu}_e}. Check: A=228=228+0A = 228 = 228 + 0, Z=88=89+(−1)Z = 88 = 89 + (-1). Step 2: X89228X2892228Ac→X90228X2902228Th+X−10X2−120e+νˉXe\ce{^{228}_{89}Ac -> ^{228}_{90}Th + ^0_{-1}e + \bar{\nu}_e}. Check: A=228=228+0A = 228 = 228 + 0, Z=89=90+(−1)Z = 89 = 90 + (-1). The final nuclide is thorium-228 (X90228X2902228Th\ce{^{228}_{90}Th}), having the same mass number 228 as the initial parent radium-228 but with two additional nuclear protons.

UndergraduateUniversity tier: Q-value and decay kinematics

Q=[m(XZAX2Z2AX)−m(XZ−2A−4X2Z−22A−4Y)−m(X24X2224He)]c2,Tα≈Q⋅A−4AQ = \left[ m(\ce{^A_Z X}) - m(\ce{^{A-4}_{Z-2} Y}) - m(\ce{^4_2He}) \right] c^2, \qquad T_\alpha \approx Q \cdot \frac{A - 4}{A}

A nuclear decay occurs spontaneously only if its reaction energy QQ is positive (Q>0Q > 0), signifying that the rest mass of the parent exceeds the combined rest masses of its decay products. In two-body alpha decay from a parent nucleus at rest, conservation of linear momentum (pα=pYp_\alpha = p_Y) dictates the kinetic energy partition between the alpha particle and the daughter nucleus. Because the alpha particle is much lighter than the recoil daughter (mα≪mYm_\alpha \ll m_Y), it carries away almost all kinetic energy: Tα=QmYmY+mα≈QA−4AT_\alpha = Q \frac{m_Y}{m_Y + m_\alpha} \approx Q \frac{A - 4}{A}, while the daughter recoils with TY≈Q4AT_Y \approx Q \frac{4}{A}.

Example: Q-value and alpha kinetic energy for uranium-238

The atomic masses of X92238X2922238U\ce{^{238}_{92}U}, X90234X2902234Th\ce{^{234}_{90}Th} and an alpha particle (X24X2224He\ce{^4_2He}) are 238.050788 u238.050788\text{ u}, 234.043601 u234.043601\text{ u} and 4.002603 u4.002603\text{ u} respectively. Using 1 u=931.494 MeV1\text{ u} = 931.494\text{ MeV}, compute the total decay energy QQ and estimate the kinetic energy TαT_\alpha carried by the alpha particle.

Solution

Mass defect: Δm=238.050788−(234.043601+4.002603)=0.004584 u\Delta m = 238.050788 - (234.043601 + 4.002603) = 0.004584\text{ u}. Decay energy: Q=0.004584×931.494≈4.270 MeVQ = 0.004584 \times 931.494 \approx 4.270\text{ MeV}. Alpha kinetic energy: Tα≈4.270×234238≈4.20 MeVT_\alpha \approx 4.270 \times \frac{234}{238} \approx 4.20\text{ MeV}. The daughter thorium nucleus retains approximately 0.07 MeV0.07\text{ MeV} of recoil kinetic energy.

AdvancedAdvanced physical depth: spectra, selection rules and internal conversion

Whereas alpha and gamma transitions produce discrete monoenergetic spectral lines characteristic of transitions between quantized nuclear levels, beta-minus decay presents a continuous energy spectrum from zero up to an endpoint Emax⁡≈QE_{\max} \approx Q. This continuous distribution led Wolfgang Pauli in 1930 to postulate the existence of the neutrino: the three-body kinematics of XZAX2Z2AX→XZ+1AX2Z+12AY+eX−+νˉXe\ce{^A_Z X -> ^A_{Z+1} Y + e- + \bar{\nu}_e} continuously partitions the available energy and angular momentum between the beta particle and the antineutrino. Furthermore, de-excitation of excited nuclear states does not occur exclusively through real gamma photons; in internal conversion (IC), electromagnetic multipole coupling transfers excitation energy directly to an inner-shell atomic electron, expelling it as a monoenergetic conversion electron followed by characteristic X-ray or Auger electron emissions. These transitions are governed by rigorous angular momentum ΔI\Delta I and parity Δπ\Delta \pi selection rules.

References

  • Introductory Nuclear Physics · K. S. Krane, 1987
  • Radiochemistry and Nuclear Chemistry, 4th Edition · G. Choppin, J.-O. Liljenzin, J. Rydberg, C. Ekberg, 2013