Problem 2
The Hill reaction dissects photosynthesis. (a) Write the overall equation of plant photosynthesis, reducing to . (b) Hill found that isolated chloroplasts do not evolve in light even with , but do so upon adding potassium ferrioxalate (with excess oxalate) without . Give the oxidant and reducing agent in natural photosynthesis and in the Hill reaction. (c) Hill measured evolved with haemoglobin (Hb binds 1:1, initial mol dm); at mol dm the HbO fraction saturates at about 75 %. Estimate the Fe/ ratio, write the Hill reaction equation, and calculate its at K, mmHg, pH = 8, standard concentrations of other species (: +1.23 V; +0.05 V). Is it spontaneous? (d) Isolated chloroplasts were irradiated 2 h with 672 nm light of 0.503 mJ s, producing 47.6 mm (10 °C, 740 mmHg). Calculate the quantum requirement (photons per electron transferred). (e) Conclusions: are water oxidation and reduction spatially separated? Is produced from ? Does water oxidation require light? Do most chlorophylls participate directly? Does each photon transfer one electron?
Step 5 of 5: Conclusions from Hill's data
Analysis
evolves without , so water oxidation is spatially and mechanistically separate from reduction and the oxygen comes from water. The endergonic shows light drives the oxidation. The quantum requirement of 2.5 (not 1) plus the saturation behaviour show that many chlorophylls form an antenna feeding a few reaction centres.