每个表面 MoSX2\ce{MoS2}MoSX2 单元含2个S和1个Mo,占 2AS+AMo=1.10×10−182A_S + A_{\ce{Mo}} = 1.10\times 10^{-18}2AS+AMo=1.10×10−18 m²,但只有一半单元在表面,故 Atot=12×1.02×10−5×6.022×1023×1.10×10−18=3.38A_{\text{tot}} = \tfrac{1}{2}\times 1.02\times 10^{-5}\times 6.022\times 10^{23}\times 1.10\times 10^{-18} = 3.38Atot=21×1.02×10−5×6.022×1023×1.10×10−18=3.38 m²。MoS2 质量为 1.2350×0.0428/95.95×160.07=0.08811.2350\times 0.0428/95.95\times 160.07 = 0.08811.2350×0.0428/95.95×160.07=0.0881 g,得 Vtot=0.0881/5.06=1.74×10−8V_{\text{tot}} = 0.0881/5.06 = 1.74\times 10^{-8}Vtot=0.0881/5.06=1.74×10−8 m³。